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21X^2+38X+16=0
a = 21; b = 38; c = +16;
Δ = b2-4ac
Δ = 382-4·21·16
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-10}{2*21}=\frac{-48}{42} =-1+1/7 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+10}{2*21}=\frac{-28}{42} =-2/3 $
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